document.write( "Question 118278: I really need help putting this into a two column proof.
\n" ); document.write( "~ How can i prove that the midpoints of the rhombus ABCD (clockwise from top) form a rectangle MNOP (clockwise from top right hand corner)? \r
\n" ); document.write( "\n" ); document.write( "some of it is explained in this website: http://www.mste.uiuc.edu/m2t2/geometry/RHMRECT.HTM\r
\n" ); document.write( "\n" ); document.write( " i understand that if i extend B and N to meet, then i can prove that the triangle is congruent and the angles are supplemetary so the angles of the rctangle must be 90 degrees, so it is a rectangle. but what if it is a square? It wil be greatly appreciated if you can put this into a two column proof for me!! THANK YOU!!
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Algebra.Com's Answer #86574 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "what if it is a square? \r
\n" ); document.write( "\n" ); document.write( "it could NOT be a square...
\n" ); document.write( "reason:\r
\n" ); document.write( "\n" ); document.write( "The diagonals of a rhombus are perpendicular bisectors of each other,but the \"lengths\" of the two diagonals for a rhombus are \"not\"\"+equal\"
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