document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118432>Question 118432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a canoe can travel 15 mi/hr in still water.  Going with the current, it can travel 20 miles in the same time that it takes to travel 10 miles against the current.  Find the rate of the current </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86545 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a canoe can travel 15 mi/hr in still water. Going with the current, it can travel 20 miles in the same time that it takes to travel 10 miles against the current. Find the rate of the current<BR>\n" );
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document.write( "Let the speed of the current be \"c\"<BR>\n" );
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document.write( "Downstream DATA:<BR>\n" );
document.write( "Distance = 20 miles ; rate = 15+c ; time = d/r = 20/(15+c) hrs<BR>\n" );
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document.write( "Upstream DATA;<BR>\n" );
document.write( "Distance = 10 miles ; rate = 15-c ; time = d/r = 10/(15-c) hrs<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "time up = time down<BR>\n" );
document.write( "10/(15-c) = 20/(15+c)<BR>\n" );
document.write( "1/(15-c) = 2/(15+c)<BR>\n" );
document.write( "15+c = 2(15-c)<BR>\n" );
document.write( "15+c = 30-2c<BR>\n" );
document.write( "3c = 15<BR>\n" );
document.write( "c = 5 mph ( speed of the current )<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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