document.write( "Question 118390: two trains traveled in opposite directions from the same starting point. one train traveled 25 mph faster than the other one. after 4 hours they were 456 miles apart. find the rate of each train. \n" ); document.write( "

Algebra.Com's Answer #86523 by rcmcc(152) $\"\"$ $\"About$

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To solve this question you must first find a linear equation.\r
\n" ); document.write( "\n" ); document.write( "Let the speed of the slower train equal (x)
\n" ); document.write( "the faster train is 25mph faster than (x) so train 2=(X)+25\r
\n" ); document.write( "\n" ); document.write( "Because 4 hours elapsed we can state that (4)(X) distance has occured for the slower train and (4)(x+25) has occured for the faster train.\r
\n" ); document.write( "\n" ); document.write( "Because we are looking for the total distance between them we can add them to find the total distance.
\n" ); document.write( "train x+train Y= XY
\n" ); document.write( "(4x)+(4y)=456
\n" ); document.write( "because y (faster train) is represented by x+25. substitute the value.\r
\n" ); document.write( "\n" ); document.write( "your linear equation is below\r
\n" ); document.write( "\n" ); document.write( "4(X)+(4)(x+25)=456
\n" ); document.write( "expand the brackets and simplify the equation and solve
\n" ); document.write( "4x+4x+100=456
\n" ); document.write( "8x+100=456
\n" ); document.write( "8x=356
\n" ); document.write( "x=44.5\r
\n" ); document.write( "\n" ); document.write( "so the slower train is traveling at 44.5mph and the faster one is traveling at 69.5.\r
\n" ); document.write( "\n" ); document.write( "You can test this by substituting the numbers into your equation (4x)+(4y)=456
\n" ); document.write( "(4)(44.5)+(4)(69.5)=456.\r
\n" ); document.write( "\n" ); document.write( "Solved. \n" ); document.write( "

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