document.write( "Question 118400: Please help me solve this problem. I have no idea how to arrange word problems .\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle to the nearest thousandth. Place your answers in the blanks provided.
\n" ); document.write( "Width = __________cm, Length = _________cm.
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Algebra.Com's Answer #86521 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "The length \"L\" of a rectangle is \"3+cm\" more than \"2\" times its width \"W\". \r
\n" ); document.write( "\n" ); document.write( "then \"L+=+2W+%2B+3cm\"\r
\n" ); document.write( "\n" ); document.write( "If the area \"A\" of the rectangle is \"93+cm%5E2\" \r
\n" ); document.write( "\n" ); document.write( "to find: the dimensions of the rectangle to the nearest thousandth. \r
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\n" ); document.write( "\n" ); document.write( "since the area is \"A+=+L%2AW\", we will have:\r
\n" ); document.write( "\n" ); document.write( "\"93cm%5E2++=+%282W+%2B+3%29%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"0+=+2W%5E2+%2B+3W+-+93+cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"+2W%5E2+%2B+3W+-+93+cm%5E2+=+0\"..\r
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\n" ); document.write( "\n" ); document.write( "find only positive root ( the width cannot be negative)\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-3+%2B-+sqrt+%283%5E2+-4%2A2%2A%28-93%29+%29%29+%2F+%282%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-3+%2B-+sqrt+%289+%2B+744+%29%29+%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-3+%2B-+sqrt+%28+753%29%29+%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-3+%2B-+27.44%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%5D=%28-3%2B+27.44%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%5D=%28+24.44%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%5D=+6.11cm\"..then\r
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\n" ); document.write( "\n" ); document.write( "\"L+=+2+%2A+6.11cm+%2B+3cm\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+12.22cm+%2B+3cm\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+15.22cm+\"\r
\n" ); document.write( "\n" ); document.write( "check:\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"93cm%5E2=+15.22cm+%2A6.11cm\"\r
\n" ); document.write( "\n" ); document.write( "\"93cm%5E2=+92.9942cm%5E2\".........we can round it\r
\n" ); document.write( "\n" ); document.write( "\"93cm%5E2=+93cm%5E2\".........\r
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\n" ); document.write( "\n" ); document.write( "\"Width+=+6.11cm\", \"Length+=+15.22cm+\"
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