document.write( "Question 118400: Please help me solve this problem. I have no idea how to arrange word problems .\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle to the nearest thousandth. Place your answers in the blanks provided.
\n" ); document.write( "Width = __________cm, Length = _________cm.
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Algebra.Com's Answer #86518 by stanbon(75887)\"\" \"About 
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The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle to the nearest thousandth.
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\n" ); document.write( "Let the width be x cm ;Then the length is 2x+3 cm
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\n" ); document.write( "Area = width*length
\n" ); document.write( "93 = x(2x+3)
\n" ); document.write( "93 = 2x^2+3x
\n" ); document.write( "2x^2+3x-93 = 0
\n" ); document.write( "x = [-3 +- sqrt(9 -4*2*-93)]/4
\n" ); document.write( "x = [-3 + sqrt(753)]/4
\n" ); document.write( "x = [-3 + 27.44]/4
\n" ); document.write( "x = 24.44/4
\n" ); document.write( "x = 6.11 cm (width)
\n" ); document.write( "2x+3 = 15.22 cm (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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