document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118385>Question 118385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pat invested a total of $3,000.  Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year.  If the total yearly interest from this investment is $256, how much did Pat invest at 10% and how much at 8%?\r<BR>\n" );
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document.write( "I assume this problem uses the I=P*RT equation, but with a twist.  I have tried to come up with several formulas with no avail. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86503 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "YOU ARE RIGHT ON!!!!!!!!!!!!!!!\r<BR>\n" );
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document.write( "I=PRT IS THE FORMULA THAT NEEDS TO BE USED AND WE'LL USE IT:\r<BR>\n" );
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document.write( "Let P=amount of money invested at 10%<BR>\n" );
document.write( "Then (3000-P)=amount invested at 8%\r<BR>\n" );
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document.write( "Interest on the money invested at 10% for 1 year=P*0.10*1 (the formula)<BR>\n" );
document.write( "Interest on the money invested at 8% fro 1 year=(3000-P)*0.08*1\r<BR>\n" );
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document.write( "Now we are told that the above interest adds up to $256, so our equation to solve is:\r<BR>\n" );
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document.write( "0.10P+0.08(3000-P)=256  get rid of parens\r<BR>\n" );
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document.write( "0.10P+240-0.08P=256 subtract 240 from both sides\r<BR>\n" );
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document.write( "0.10P+240-240-0.08P=256-240  collect like terms\r<BR>\n" );
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document.write( "0.02P=16  divide both sides by 0.02<BR>\n" );
document.write( "P=$800-----------------------------------------amount invested at 10%\r<BR>\n" );
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document.write( "3000-P=3000-800=$2200----------------------------amount invested at 8%\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "800*0.10+2200*0.08=256<BR>\n" );
document.write( "80+176=256<BR>\n" );
document.write( "256=256\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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