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document.write( "numerator sqrt5-2x denominator 3 =1 \n" );
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Algebra.Com's Answer #86492 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! sqrt(5-2x)/3=1 cross multiply \n" ); document.write( "sqrt(5-2x)=3 square both sides \n" ); document.write( "5-2x=9 \n" ); document.write( "-2x=9-5 \n" ); document.write( "-2x=4 \n" ); document.write( "x=4/-2 \n" ); document.write( "x=-2 answer. \n" ); document.write( "proof \n" ); document.write( "sqrt(5-2*-2)/3=1 \n" ); document.write( "sqrt(5+4)/3=1 \n" ); document.write( "sqrt9/3=1 \n" ); document.write( "sqrt9=3 \n" ); document.write( "3=3 \n" ); document.write( " |