document.write( "Question 117091: \r
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\n" ); document.write( "\n" ); document.write( "numerator sqrt5-2x denominator 3 =1
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Algebra.Com's Answer #86492 by checkley71(8403)\"\" \"About 
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sqrt(5-2x)/3=1 cross multiply
\n" ); document.write( "sqrt(5-2x)=3 square both sides
\n" ); document.write( "5-2x=9
\n" ); document.write( "-2x=9-5
\n" ); document.write( "-2x=4
\n" ); document.write( "x=4/-2
\n" ); document.write( "x=-2 answer.
\n" ); document.write( "proof
\n" ); document.write( "sqrt(5-2*-2)/3=1
\n" ); document.write( "sqrt(5+4)/3=1
\n" ); document.write( "sqrt9/3=1
\n" ); document.write( "sqrt9=3
\n" ); document.write( "3=3
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