document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118352>Question 118352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectangle is 68 cm^2, find the dimensions of the rectangle to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86470 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectangle is 68 cm^2, find the dimensions of the rectangle to the nearest thousandth.<BR>\n" );
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document.write( "Let width be \"x\" cm ; Then length is \"5x+2\" cm.<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "x(5x+2) = 68<BR>\n" );
document.write( "5x^2+2x-68=0<BR>\n" );
document.write( "x = [-2 +- sqrt(4-4*5*-68)]/10<BR>\n" );
document.write( "x = [-2 +- sqrt(4+1360)]/10<BR>\n" );
document.write( "x = [-2 +- sqrt(1364)]/10<BR>\n" );
document.write( "x = [-2 +- 36.9324]/10<BR>\n" );
document.write( "Positive answer:<BR>\n" );
document.write( "x = 3.4932 cm (width)<BR>\n" );
document.write( "5x+2 = 19.4662 cm (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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