document.write( "Question 118352: The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectangle is 68 cm^2, find the dimensions of the rectangle to the nearest thousandth. \n" ); document.write( "
Algebra.Com's Answer #86469 by MathLover1(20850)\"\" \"About 
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The length: \"L\"
\n" ); document.write( "The width: \"W\"
\n" ); document.write( "the area: \"A=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"L+=+5W+%2B+2cm\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+68+cm%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+L%2AW\"…………….substitute \"L\" and \"A\"\r
\n" ); document.write( "\n" ); document.write( "\"68+cm%5E2+=+%285W+%2B+2cm+%29%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"68+cm%5E2+=+5W%5E2+%2B+2cm%2AW+\"\r
\n" ); document.write( "\n" ); document.write( "\"+5W%5E2+%2B+2cm%2AW+-+68+cm%5E2+=+0+\"……………use quadratic formula to solve for \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-b+%2B-+sqrt+%28b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-+2cm+%2B-+sqrt+%284cm%5E2+%2B+1360cm%5E2+%29%29+%2F+10\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-+2cm+%2B-+sqrt+%281364cm%5E2+%29%29+%2F+10\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5B1%2C2%5D=%28-+2cm+%2B-+36.9cm%29+%2F+10\"….
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\n" ); document.write( "\n" ); document.write( "Since we are looking for the width, we need only positive root:\r
\n" ); document.write( "\n" ); document.write( "\"W%5B1%5D=%28-+2cm+%2B+36.9cm%29+%2F+10\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5B1%5D=%28+34.9cm%29+%2F+10\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5B1%5D=%28+3.49cm%29+\"
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\n" ); document.write( "Now we can find the length;\r
\n" ); document.write( "\n" ); document.write( "\"L+=+5W+%2B+2cm\"….substitute \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+5%283.49cm+%29+%2B+2cm\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+17.45cm+%2B+2cm\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+19.45cm+\"\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"A+=+L%2AW\"…………….\r
\n" ); document.write( "\n" ); document.write( "\"A+=+%2819.45cm%29%283.49cm+%29\"…………….\r
\n" ); document.write( "\n" ); document.write( "\"A+=+%2867.8805cm%5E2%29\"…………….which can be rounded to \"68cm%5E2\"
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