document.write( "Question 118342: The sum of the ages of Dorothy and Dorileen is 41. In 5 years, Dorothy will be twice as old as Dorileen. Find their age 3 years ago. \n" ); document.write( "
Algebra.Com's Answer #86461 by ankor@dixie-net.com(22740)\"\" \"About 
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Let x = Dorthy's age 3 yrs ago
\n" ); document.write( "Let y = Dorileen's age 3 yrs ago
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\n" ); document.write( "There present age will be: (x+3) and (y+3)
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\n" ); document.write( "\"The sum of the ages of Dorothy and Dorileen is 41.\"
\n" ); document.write( "(x+3) + (y+3) = 41
\n" ); document.write( "x + y + 6 = 41
\n" ); document.write( "x + y = 41 - 6
\n" ); document.write( "x + y = 35
\n" ); document.write( "x = (35 - y)
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\n" ); document.write( "\" In 5 years, Dorothy will be twice as old as Dorileen.\"
\n" ); document.write( "(That will be 8 yrs from 3 yrs ago)
\n" ); document.write( "x + 8 = 2(y + 8)
\n" ); document.write( "x + 8 = 2y + 16
\n" ); document.write( "x = 2y + 16 - 8
\n" ); document.write( "x = 2y + 8
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\n" ); document.write( "\"Find their ages 3 yrs ago\"
\n" ); document.write( "Substitute (35-y) for x and find y
\n" ); document.write( "35 - y = 2y + 8
\n" ); document.write( "35 - 8 = 2y + y
\n" ); document.write( "3y = 27
\n" ); document.write( "y = 27/3
\n" ); document.write( "y = 9 yrs old is Dorileen's age 3 yrs ago
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\n" ); document.write( "35 - 9 = 26 yrs is Dorthy's age 3 yrs ago
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\n" ); document.write( "Check solution using the statement:
\n" ); document.write( "\"The sum of the ages of Dorothy and Dorileen is 41.\"
\n" ); document.write( "(26+3) + (9+3) =
\n" ); document.write( "29 + 12 = 41
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