document.write( "Question 118286: jessie kicked a soccer ball into the air with an initial upward velocity of 40 feet per second. The hieght (h) in feet of the ball above the ground can be modeled by h=-16t2+40t,where t is the time in seconds after jessie kicked the ball. find the time it takes the ball to reach 25 feet above the grond. \n" ); document.write( "
Algebra.Com's Answer #86408 by jim_thompson5910(35256)\"\" \"About 
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Since we're finding the time it takes for the ball to reach 25 feet, this means h is 25\r
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\n" ); document.write( "\n" ); document.write( "\"h=-16t%5E2%2B40t\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"25=-16t%5E2%2B40t\" Plug in \"h=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"16t%5E2-40t%2B25=0\" Add \"16t%5E2\" to both sides. Subtract \"40t\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"16%2Ax%5E2-40%2Ax%2B25=0\" ( notice \"a=16\", \"b=-40\", and \"c=25\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28--40+%2B-+sqrt%28+%28-40%29%5E2-4%2A16%2A25+%29%29%2F%282%2A16%29\" Plug in a=16, b=-40, and c=25\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2840+%2B-+sqrt%28+%28-40%29%5E2-4%2A16%2A25+%29%29%2F%282%2A16%29\" Negate -40 to get 40\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2840+%2B-+sqrt%28+1600-4%2A16%2A25+%29%29%2F%282%2A16%29\" Square -40 to get 1600 (note: remember when you square -40, you must square the negative as well. This is because \"%28-40%29%5E2=-40%2A-40=1600\".)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2840+%2B-+sqrt%28+1600%2B-1600+%29%29%2F%282%2A16%29\" Multiply \"-4%2A25%2A16\" to get \"-1600\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2840+%2B-+sqrt%28+0+%29%29%2F%282%2A16%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2840+%2B-+0%29%2F%282%2A16%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2840+%2B-+0%29%2F32\" Multiply 2 and 16 to get 32\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2840+%2B+0%29%2F32\" or \"x+=+%2840+-+0%29%2F32\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2840+%2B+0%29%2F32\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=40%2F32\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=5%2F4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=5%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2840+-+0%29%2F32\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=40%2F32\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=5%2F4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=5%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "So our only solution is:\r
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\n" ); document.write( "\n" ); document.write( "\"x=5%2F4\" (which is \"x=1.25\" in decimal form)\r
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\n" ); document.write( "\n" ); document.write( "So at 1.25 seconds, the ball is 25 feet high.
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