document.write( "Question 118284: Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? \n" ); document.write( "
Algebra.Com's Answer #86406 by stanbon(75887) ![]() You can put this solution on YOUR website! Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? \n" ); document.write( "------------------- \n" ); document.write( "Martina DATA: \n" ); document.write( "Rate = 24 mph ; Time = x hrs ; distance = rt = 24x miles \n" ); document.write( "---------------------------- \n" ); document.write( "John DATA: \n" ); document.write( "Rate = 48 mph ; Time = x-2 ; distance = rt = 48(x-2) miles \n" ); document.write( "------------------------------ \n" ); document.write( "EQUATION: \n" ); document.write( "Martina distance = John distance \n" ); document.write( "24x = 48(x-2) \n" ); document.write( "24x = 48x-96 \n" ); document.write( "24x = 96 \n" ); document.write( "x = 4 hrs \n" ); document.write( "-------------- \n" ); document.write( "John will catch Martina at 9:00 AM = 4 hrs = 1:00 PM \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |