document.write( "Question 118284: Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? \n" ); document.write( "
Algebra.Com's Answer #86406 by stanbon(75887)\"\" \"About 
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Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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\n" ); document.write( "Martina DATA:
\n" ); document.write( "Rate = 24 mph ; Time = x hrs ; distance = rt = 24x miles
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\n" ); document.write( "John DATA:
\n" ); document.write( "Rate = 48 mph ; Time = x-2 ; distance = rt = 48(x-2) miles
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\n" ); document.write( "EQUATION:
\n" ); document.write( "Martina distance = John distance
\n" ); document.write( "24x = 48(x-2)
\n" ); document.write( "24x = 48x-96
\n" ); document.write( "24x = 96
\n" ); document.write( "x = 4 hrs
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\n" ); document.write( "John will catch Martina at 9:00 AM = 4 hrs = 1:00 PM
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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