document.write( "Question 118267: How do you write this equation of ellipse in simple form?\r
\n" ); document.write( "\n" ); document.write( "3x^2 + 4y^2 + 8y=8
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\n" ); document.write( " * I tried dividing everything by eigth leaving me with:\r
\n" ); document.write( "\n" ); document.write( " 3x^2/8 +y^2/2 + y=1
\n" ); document.write( " But when i checked to see if i had the right answer i got it wrong this is the correct answer:
\n" ); document.write( " x^2/4 + (y+1)^2/3=1\r
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\n" ); document.write( "\n" ); document.write( " I don't understand why i got the problem wrong.
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Algebra.Com's Answer #86386 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The standard form for the equation of an ellipse with center at (h, k) and major axis parallel to the x-axis is: (a is the semi-major axis and b is the semiminor axis)
\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1\" or, if the major axis is parallel to the y-axis:
\n" ); document.write( "\"%28x-h%29%5E2%2Fb%5E2+%2B+%28y-k%29%5E2%2Fa%5E2+=+1\"
\n" ); document.write( "Starting with the given equation:
\n" ); document.write( "\"3x%5E2%2B4y%5E2%2B8y+=+8\" Group the terms as shown:
\n" ); document.write( "\"%283x%5E2%29%2B%284y%5E2%2B8y%29+=+8\" Now factor a 4 from the y-group.
\n" ); document.write( "\"%283x%5E2%29%2B4%28y%5E2%2B2y%29+=+8\" Now complete the square in the y-terms inside the parentheses by adding the square of half the y-coefficient or (\"%282%2F2%29%5E2+=+1\"), remembering that you are really adding 4 because of the 4 in front of the parentheses.
\n" ); document.write( "\"%283x%5E2%29%2B4%28y%5E2%2B2y%2B1%29+=+8%2B4\" Now simplify this by factoring the trinomial in the y-terms.
\n" ); document.write( "\"%283x%5E2%29%2B4%28y%2B1%29%5E2+=+12\" Now divide through by 12 to get the right side equal to 1.
\n" ); document.write( "\"%283%2F12%29x%5E2+%2B+%284%2F12%29%28y%2B1%29%5E2+=+12%2F12\" Simplify this.
\n" ); document.write( "\"x%5E2%2F4+%2B+%28y%2B1%29%5E2%2F3+=+1\"
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