document.write( "Question 118260This question is from textbook Elementary and Intermediate Algebra
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document.write( ": x2 + x + sqr root of x2 + x -2 = 0\r
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document.write( "b4 + 13b2 + 36 = 0 \n" );
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Algebra.Com's Answer #86381 by stanbon(75887) ![]() You can put this solution on YOUR website! x^2 + x + [sqr root of (x^2 + x -2)] = 0 \n" ); document.write( "sqrt(x^2+x-2) = -(x^2+x) \n" ); document.write( "Square both sides to get: \n" ); document.write( "x^2+x-2 = x^4 + 2x^3+ x^2 \n" ); document.write( "x^4- 2x^3 +2 = 0 \n" ); document.write( "-------- \n" ); document.write( "This equation has no Real Number solutions. \n" ); document.write( "----------------------------\r \n" ); document.write( "\n" ); document.write( "b^4 + 13b^2 + 36 = 0 \n" ); document.write( "(b^2+9)(b^2+4) = 0 \n" ); document.write( "(b+3i)(b-3i)(b-2i)(b+2i) = 0 \n" ); document.write( "b = -3i or b=3i or b=2i or b=-2i \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |