document.write( "Question 118260This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": x2 + x + sqr root of x2 + x -2 = 0\r
\n" ); document.write( "\n" ); document.write( "b4 + 13b2 + 36 = 0
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Algebra.Com's Answer #86381 by stanbon(75887)\"\" \"About 
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x^2 + x + [sqr root of (x^2 + x -2)] = 0
\n" ); document.write( "sqrt(x^2+x-2) = -(x^2+x)
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x^2+x-2 = x^4 + 2x^3+ x^2
\n" ); document.write( "x^4- 2x^3 +2 = 0
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\n" ); document.write( "This equation has no Real Number solutions.
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\n" ); document.write( "\n" ); document.write( "b^4 + 13b^2 + 36 = 0
\n" ); document.write( "(b^2+9)(b^2+4) = 0
\n" ); document.write( "(b+3i)(b-3i)(b-2i)(b+2i) = 0
\n" ); document.write( "b = -3i or b=3i or b=2i or b=-2i
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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