document.write( "Question 118243: Two (2) planes leave at the same time. One flies west 300 km per hour. The other flies east 450 km per hour. In how many hours will they be 2 250 km apart. \n" ); document.write( "
Algebra.Com's Answer #86355 by tutorcecilia(2152)\"\" \"About 
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Use the distance formula for each flight: Distance = (rate)(time)
\n" ); document.write( "Plane #1
\n" ); document.write( "Distance = (300)(t)
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\n" ); document.write( "\n" ); document.write( "Plane #2
\n" ); document.write( "Distance = (450)(t)
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\n" ); document.write( "Since their total distance is 2,250 miles and their time (t) will be the same, add their (rate)(time)+ (rate)(time)=2250, together:
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\n" ); document.write( "300t+450t=2,250 [solve for time (t)]
\n" ); document.write( "470t=2250
\n" ); document.write( "t=2250/470
\n" ); document.write( "t=3 hours
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\n" ); document.write( "Checking:
\n" ); document.write( "Plane #1
\n" ); document.write( "d=(300)(3)=900
\n" ); document.write( "Plane #2:
\n" ); document.write( "d=(450)(3)=1350
\n" ); document.write( "Adding their miles together (rate)(time) + (rate)(time) = 900+1350=2250\r
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