document.write( "Question 118211: heloo! i need some help on this question\r
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document.write( "the length of a rectangle is 5cm longer than its width. The perimeter is 54cm. Find the dimensions of the rectangle.?? \n" );
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Algebra.Com's Answer #86313 by checkley71(8403) ![]() You can put this solution on YOUR website! L=W+5 \n" ); document.write( "PERIMETER=2L+2W \n" ); document.write( "54=2(W+5)+2W \n" ); document.write( "54=2W+10+2W \n" ); document.write( "4W=54-10 \n" ); document.write( "4W=44 \n" ); document.write( "W=44/4 \n" ); document.write( "W=11 ANSWER FOR THE WIDTH. \n" ); document.write( "L=11+5=16 FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "54=2*11+2*16 \n" ); document.write( "54=22+32 \n" ); document.write( "54=54 \n" ); document.write( " \n" ); document.write( " |