document.write( "Question 118211: heloo! i need some help on this question\r
\n" ); document.write( "\n" ); document.write( "the length of a rectangle is 5cm longer than its width. The perimeter is 54cm. Find the dimensions of the rectangle.??
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Algebra.Com's Answer #86313 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
L=W+5
\n" ); document.write( "PERIMETER=2L+2W
\n" ); document.write( "54=2(W+5)+2W
\n" ); document.write( "54=2W+10+2W
\n" ); document.write( "4W=54-10
\n" ); document.write( "4W=44
\n" ); document.write( "W=44/4
\n" ); document.write( "W=11 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=11+5=16 FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "54=2*11+2*16
\n" ); document.write( "54=22+32
\n" ); document.write( "54=54
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