document.write( "Question 118215: An airplane traveled 2660 miles in 3.5 hours with a tail wind. The return trip took 3.8 hours with a head wind. What was the speed of the airplane in still air? What was the speed of the wind? Solve by using a system oi\f equations. \n" ); document.write( "
Algebra.Com's Answer #86312 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2660/3.5=760 MPH FOR THE ORIGINAL TRIP \n" ); document.write( "2660/3.8=700 MPH FOR THE RETURN TRIP \n" ); document.write( "760-W=700=W \n" ); document.write( "-2X=-60 \n" ); document.write( "X=-60/-2 \n" ); document.write( "X=30 MPH FOR THE WIND. \n" ); document.write( "760-30=730 MPH FOR THE PLANE IN STILL AIR. \n" ); document.write( " \n" ); document.write( " |