document.write( "Question 118200: I'm trying to solve the following equation:
\n" ); document.write( "The square root of [x+10] plus the square root of [x-6] equals 8.
\n" ); document.write( "I tried squaring both sides, and that eliminates some radicals, but it also creates some more!
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Algebra.Com's Answer #86300 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The square root of [x+10] plus the square root of [x-6] equals 8.
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\n" ); document.write( "\"sqrt%28x%2B10%29\" + \"sqrt%28x-6%29\" = 8
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\n" ); document.write( "Subtract \"sqrt%28x-6%29\" from both sides:
\n" ); document.write( "\"sqrt%28x%2B10%29\" = 8 - \"sqrt%28x-6%29\"
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\n" ); document.write( "Square both sides, (FOIL the right side)
\n" ); document.write( "x + 10 = 64 - 8\"sqrt%28x-6%29\" - \"sqrt%28x-6%29\" + (x-6)
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\n" ); document.write( "x + 10 = 64 - 6 - 16\"sqrt%28x-6%29\" + x
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\n" ); document.write( "x + 10 = 58 + x - 16\"sqrt%28x-6%29\"
\n" ); document.write( ":
\n" ); document.write( "x - x + 10 - 58 = 16\"sqrt%28x-6%29\"
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\n" ); document.write( "-48 = -16\"x-6%29\"
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\n" ); document.write( "Square the equation again:
\n" ); document.write( "2304 = 256(x-6)
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\n" ); document.write( "2304 = 256x - 1536
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\n" ); document.write( "256x = 2304 + 1536
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\n" ); document.write( "256x = 3840
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\n" ); document.write( "x = 3840/256
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\n" ); document.write( "x = 15
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\n" ); document.write( "Check in the original equation
\n" ); document.write( "\"sqrt%2815%2B10%29\" + \"sqrt%2815-6%29\" = 8
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