document.write( "Question 114804: The length of a rectangle is 5cm more than twice the width. The preimeter of the rectangle is 34cm. Find the fimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #86295 by tiger(2)\"\" \"About 
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let the width of trhe rectangle = x
\n" ); document.write( "so, length = x+5\r
\n" ); document.write( "\n" ); document.write( "so, perimeter :- 2{(x+5)+x}=34
\n" ); document.write( " 2(2x+5)=34
\n" ); document.write( " 4x+10=34
\n" ); document.write( " 4x=34-10
\n" ); document.write( " x=24/4=6\r
\n" ); document.write( "\n" ); document.write( "so length=11
\n" ); document.write( " width =6
\n" ); document.write( "
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