document.write( "Question 118192: when solving inequalities, how do you know whether to add or to subtract on both sides? Can you explain with an example? \n" ); document.write( "
Algebra.Com's Answer #86294 by bucky(2189)\"\" \"About 
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You can work inequalities just as you would work and equation ... same rules: \r
\n" ); document.write( "\n" ); document.write( "If you add a number on one side of the inequality you must also add the same number to the
\n" ); document.write( "other side of the inequality.
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\n" ); document.write( "If you subtract a number from one side of the inequality you must also subtract the same number
\n" ); document.write( "from the other side of the inequality.
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\n" ); document.write( "If you multiply one side of an inequality by a number, you must also multiply the other side
\n" ); document.write( "of the inequality by the same number.
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\n" ); document.write( "If you divide one side of an inequality by a number, you must also multiply the other side
\n" ); document.write( "of the inequality by the same number.
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\n" ); document.write( "One exception you must remember ... if you multiply or divide both sides of an inequality
\n" ); document.write( "by a NEGATIVE quantity, then you must reverse the direction of the inequality sign each time
\n" ); document.write( "you multiply or divide by a negative.
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\n" ); document.write( "And, just as you do with an equation, you solve it for the positive value of the variable.
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\n" ); document.write( "Suppose you have the inequality 2x + 5 < 5x - 1 and you want to solve it. You can sort
\n" ); document.write( "of imagine that the inequality sign is an equal sign while you do the work.
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\n" ); document.write( "First get rid of the + 5 on the left side by subtracting 5 from both sides. When you do that you
\n" ); document.write( "get:
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\n" ); document.write( "2x < 5x - 6
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\n" ); document.write( "Next get rid of the 5x on the right side by subtracting 5x from both sides, just as you would
\n" ); document.write( "do in an equation. After that subtraction from both sides you have:
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\n" ); document.write( "-3x < -6
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\n" ); document.write( "You can now solve for +x by dividing both sides by -3 to get:
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\n" ); document.write( "x < -6/-3
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\n" ); document.write( "BUT you divided both sides by -3 a negative number so you have to reverse the direction of
\n" ); document.write( "the inequality sign which results in:
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\n" ); document.write( "x > -6/-3
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\n" ); document.write( "Now just do the division on the right side and you get the answer:
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\n" ); document.write( "x > 2
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\n" ); document.write( "Not too bad, once you get used to the process. You can check your answer by selecting a
\n" ); document.write( "value of x that is greater than 2 and seeing if it works in the original inequality. The
\n" ); document.write( "original inequality was:
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\n" ); document.write( "2x + 5 < 5x - 1
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\n" ); document.write( "Let x be 3 and it becomes:
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\n" ); document.write( "2(3) + 5 < 5(3) - 1
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\n" ); document.write( "Which simplifies to:
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\n" ); document.write( "6 + 5 < 15 - 1
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\n" ); document.write( "Combine the numbers on both sides and you have:
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\n" ); document.write( "11 < 14
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\n" ); document.write( "That's true ... 11 is less than 14. So that seems to work. Next let x = 2 which means that
\n" ); document.write( "you have chosen a value for x that is NOT GREATER than 2. The original inequality is:
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\n" ); document.write( "2x + 5 < 5x - 1
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\n" ); document.write( "Substitute 2 for x and it becomes:
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\n" ); document.write( "2(2) + 5 < 5(2) - 1
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\n" ); document.write( "Do the multiplications and you get:
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\n" ); document.write( "4 + 5 < 10 - 1
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\n" ); document.write( "Combine the numbers on both sides and you have:
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\n" ); document.write( "9 < 9
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\n" ); document.write( "This is not true because 9 is not less than 9 ... it is equal to 9. It looks as if the answer
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\n" ); document.write( "x > 2
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\n" ); document.write( "is the correct solution to the problem.
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\n" ); document.write( "Hope this gives you some help in working inequality problems. If you still need additional help,
\n" ); document.write( "re-post some more problems.
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\n" ); document.write( "And Happy 2008 to you and yours ...
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