document.write( "Question 118184This question is from textbook Fund of Trig and Alg
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document.write( ": Hi, I am trying to review for a final and am stuck on this one.
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document.write( "Use method of substitution to solve system:\r
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document.write( "x-y^3=1
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document.write( "2x=9y^2+2\r
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document.write( "This is what I have done:
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document.write( "x=1+y^3
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document.write( "2(1+y^3)= 9y^2+2
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document.write( "2+2y^3=9y^2+2
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document.write( "2y^3=9y^2+2
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document.write( "2y^3-9y^2=0
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document.write( "y(y+3)(y-3) \n" );
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Algebra.Com's Answer #86287 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Use method of substitution to solve system:\r \n" ); document.write( "\n" ); document.write( "x-y^3=1 \n" ); document.write( "2x=9y^2+2\r \n" ); document.write( "\n" ); document.write( "This is what I have done: \n" ); document.write( "x=1+y^3 \n" ); document.write( "2(1+y^3)= 9y^2+2 \n" ); document.write( "2+2y^3 = 9y^2+2 \n" ); document.write( "2y^3=9y^2 \n" ); document.write( "2y^3-9y^2=0 \n" ); document.write( "y^2(2y-9) = 0 \n" ); document.write( "y = 0 or y = 9/2 \n" ); document.write( "--------------------- \n" ); document.write( "Now solve for \"x\": \n" ); document.write( "If y = 0, x = 0^3+1 = 1 \n" ); document.write( "If y = (9/2), x = (9/2)^3+1 = 729/8+1 = 737/8= 91 1/8 \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |