document.write( "Question 118183: Hello out there,I need help with two tough problems,the first one is,Solve:3y/2=7+y/4.And the last one is,Find the quotient:e^2-e-12/e-4,thanks to whoever can help. \n" ); document.write( "
Algebra.Com's Answer #86279 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"3y%2F2=7%2By%2F4\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%284%29%283y%2F2%29=%284%29%287%2By%2F4%29\" Multiply both sides by the LCM of 4. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"6y=28%2By\" Distribute and multiply the LCM to each side\r
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\n" ); document.write( "\n" ); document.write( "\"6y=28%2By\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"6y-y=28\" Subtract y from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"5y=28\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"y=%2828%29%2F%285%29\" Divide both sides by 5 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=28%2F5\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"y=28%2F5\" (which is approximately \"y=5.6\" in decimal form)\r
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\n" ); document.write( "\n" ); document.write( "\"%28e%5E2-e-12%29%2F%28e-4%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28e-4%29%28e%2B3%29%29%2F%28e-4%29\" Factor \"e%5E2-e-12\" to get \"%28e-4%29%28e%2B3%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"%28e-4%29%28e%2B3%29%2F%28e-4%29\" Combine the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"cross%28%28e-4%29%29%28e%2B3%29%2Fcross%28%28e-4%29%29\" Cancel like terms\r
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\n" ); document.write( "\n" ); document.write( "\"e%2B3\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So \"%28e%5E2-e-12%29%2F%28e-4%29\" simplifies to \"e%2B3\". In other words \"%28e%5E2-e-12%29%2F%28e-4%29=e%2B3\"\r
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