document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118170>Question 118170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when solving inequalities, how do you know whether to subtract or to add on \r<BR>\n" );
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document.write( "both sides? for example, 5x-4<6x+2.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86266 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5X-4<6X+2 GENERALLY I LIKE THE UNKNOWN TERM ON THE LEFT SIDE. THUS:<BR>\n" );
document.write( "5X-6X<2+4<BR>\n" );
document.write( "-X<6 NOW WHEN YOU DIVIDE BY -1 THE < SIGN CHANGES TO THE > SIGN.<BR>\n" );
document.write( "X>6/-1<BR>\n" );
document.write( "X>-6 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "LET X=-5.9<BR>\n" );
document.write( "5(-5.9)-4<6(-5.9)+2<BR>\n" );
document.write( "-29.5-4<-35.4+2<BR>\n" );
document.write( "-33.5<-33.4 </SPAN>\n" );
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