document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118151>Question 118151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello i need some help on this thankyou\r<BR>\n" );
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document.write( "Mrs. Maaza is 3 times as old as her son. In 12 years Mrs. MAaza will be twice as old. How old is her son now.?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86265 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's say Mrs. Maaza is x years old and her son is y years old.<BR>\n" );
document.write( "So x=3y and x+12=2(y+12).  Now we have a system of equations to solve.<BR>\n" );
document.write( "So plug 3y in for x in the second equation.  3y+12=2y+24 (using distribution).<BR>\n" );
document.write( "Solving for y gives y=12.  So the son is 12 years old.  Let's check.  If he is 12, she is 3*12=36.  In 12 years, she will then be 48 and he will be 24, so it works:) </SPAN>\n" );
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