document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118156>Question 118156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know this may not be the right topic for the problem but i guessed.\r<BR>\n" );
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document.write( "which is a solution of the system?   -2x+y less than and equal to 8<BR>\n" );
document.write( "                                     x-3y greater 9\r<BR>\n" );
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document.write( "a. (0,-3)<BR>\n" );
document.write( "b. (0,9)<BR>\n" );
document.write( "c. both a and b<BR>\n" );
document.write( "d. neither a nor b  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86264 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a, x=0 and y=-3.  For b, x=0 and y=9.  So you need to plug in each pair and see which makes both inequalities true.<BR>\n" );
document.write( "For a, -2x+y = 0-3 = -3.  This is less than or equal to 8, so that one works.<BR>\n" );
document.write( "Again for a, x-3y = 0+9 = 9, which is not greater than 9.  So a does not work.<BR>\n" );
document.write( "For b, -2x+y = 0+9 = 9, which is not less than or equal to 8, so b already fails.<BR>\n" );
document.write( "So the answer is d, neither will work. </SPAN>\n" );
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