document.write( "Question 118137: Betty's present age is twice Roni's present age. Two years ago, Betty was three times as old as Roni was then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #86250 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! Roni's = x \n" ); document.write( "Betty's age = 2x \n" ); document.write( "~~~~ \n" ); document.write( "Roni's = x - 2 \n" ); document.write( "Betty's age = 3(x - 2) = 3x - 6 \n" ); document.write( "~~~~ \n" ); document.write( "2x - 2 = 3x - 6 \n" ); document.write( "-2 = x - 6 \n" ); document.write( "4 = x \n" ); document.write( "~~~~ \n" ); document.write( "Roni's = x = 4 years \n" ); document.write( "Betty's age = 2x = 8 years \n" ); document.write( " |