document.write( "Question 118121: Solve.\r
\n" ); document.write( "\n" ); document.write( "square root of 4x+4 -8=0\r
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\n" ); document.write( "\n" ); document.write( "2+ square root of 3x-2 = 0
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Algebra.Com's Answer #86233 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
square root of 4x+4 -8=0
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\n" ); document.write( "\"sqrt%284x%2B4%29\" - 8 = 0
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\n" ); document.write( "Add 8 to both sides:
\n" ); document.write( "\"sqrt%284x%2B4%29\" = 8
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\n" ); document.write( "Square both sides and you have:
\n" ); document.write( "4x + 4 = 64
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\n" ); document.write( "subtract 4 from both sides:
\n" ); document.write( "4x = 64 - 4
\n" ); document.write( "4x = 60
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "x = \"60%2F4\"
\n" ); document.write( "x = 15
\n" ); document.write( ":
\n" ); document.write( "You can substitute 15 for x in the original equation and check our solution
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\n" ); document.write( "2+ square root of 3x-2 = 0
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\n" ); document.write( "2 + \"sqrt%283x-2%29\" = 0
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\n" ); document.write( "Subtract 2 from both sides
\n" ); document.write( "\"sqrt%283x-2%29\" = -2
\n" ); document.write( "You can see that his will not have a solution, but we can proceed with the method:
\n" ); document.write( "Square both sides:
\n" ); document.write( "3x - 2 = +4
\n" ); document.write( "3x = 4 + 2
\n" ); document.write( "3x = 6
\n" ); document.write( "x = \"6%2F3\"
\n" ); document.write( "x = 2
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\n" ); document.write( "Substitute 2 for x in the original equation
\n" ); document.write( "2 + \"sqrt%283%282%29-2%29\" = 0
\n" ); document.write( "2 + \"sqrt%284%29\"} = 0
\n" ); document.write( "2 + 2 does not = 0 so this is not a solution
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