document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118117>Question 118117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the second of the consecutive even integers is 14 more than the sum of the first and the third. Find the middle integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86226 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three times the second of the consecutive even integers is 14 more than the sum of the first and the third. Find the middle integer.<BR>\n" );
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document.write( "1st = 2x<BR>\n" );
document.write( "2nd = 2x+2<BR>\n" );
document.write( "3rd = 2x+4<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "3(2x+2)-14 =2x+2x+4<BR>\n" );
document.write( "6x+6-14 = 4x+4<BR>\n" );
document.write( "2x=12<BR>\n" );
document.write( "x = 6<BR>\n" );
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document.write( "2x+2 = 14<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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