document.write( "Question 118112: A jogger started a course and jogged at an average speed of 4 mph. One hour later, a cyclist started the same course and cycled at an average speed of 11 mph. How long after the jogger started did the cyclist overtake the jogger? \n" ); document.write( "
Algebra.Com's Answer #86211 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A jogger started a course and jogged at an average speed of 4 mph. One hour later, a cyclist started the same course and cycled at an average speed of 11 mph. How long after the jogger started did the cyclist overtake the jogger?
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time of the jogger
\n" ); document.write( "then
\n" ); document.write( "(t-1) = travel time of the cyclist
\n" ); document.write( ":
\n" ); document.write( "When the cyclist overtakes the jogger they will have traveled the same distance
\n" ); document.write( "Write a distance equation; distance = speed * time
\n" ); document.write( ":
\n" ); document.write( "Cyclist dist = jogger distance
\n" ); document.write( "11(t-1) = 4t
\n" ); document.write( ":
\n" ); document.write( "11t - 11 = 4t
\n" ); document.write( ":
\n" ); document.write( "11t - 4t = + 11
\n" ); document.write( ":
\n" ); document.write( "7t = 11
\n" ); document.write( ":
\n" ); document.write( "t = \"11%2F7\"
\n" ); document.write( ":
\n" ); document.write( "t = 1.57 hrs or 1 \"57%2F60\" = 1 hr 34.2 min
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution; find the distance of each:
\n" ); document.write( "1.57 * 4 = 6.28 mi
\n" ); document.write( ".57 * 11 = 6.27 mi \n" ); document.write( "
\n" );