document.write( "Question 17885: A director of a zoo wants to use 170 meters of fencing to enclose a petting area of 1750 meters squared. Find the dimensions of the petting area. \n" ); document.write( "
Algebra.Com's Answer #8619 by whisper(27)\"\" \"About 
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The given information is:
\n" ); document.write( "170 meters of fencing so that the perimeter is 170.
\n" ); document.write( "The area is to be 1750.
\n" ); document.write( "The formula for area is lxw=a
\n" ); document.write( "The formula for perimeter is 2l+2w=p
\n" ); document.write( "2l+2w=170
\n" ); document.write( "Divde by through by 2
\n" ); document.write( "2l/2+2w/2=170/2
\n" ); document.write( "l+w=85
\n" ); document.write( "subtract w or the width from both sides to get length in terms of width.
\n" ); document.write( "l+w-w=85-w
\n" ); document.write( "l+0=85-w
\n" ); document.write( "l=85-w
\n" ); document.write( "So now again recall the formula lxw=a
\n" ); document.write( "(85-w)w=1750
\n" ); document.write( "85w-w^2=1750
\n" ); document.write( "Now get everything on one side of the equation by subtracting 1750 from both sides
\n" ); document.write( "-w^2+85w-1750=85-1750
\n" ); document.write( "-w^2+85w-1750=0
\n" ); document.write( "You could solve for w here by using the quadratic formula but to solve by factoring it will be easier to multiply through by -1
\n" ); document.write( "-1(-w^2)+-1(85w)+-1(-1750)=0(-1)
\n" ); document.write( "w^2-85w+1750=0
\n" ); document.write( "(w-50)(w-35)=0
\n" ); document.write( "w-50 = 0 or w-25=0
\n" ); document.write( "So w=50 or w=25\r
\n" ); document.write( "\n" ); document.write( "Please don't hesitate to ask if you have further questions! \n" ); document.write( "
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