document.write( "Question 118073: Solve \r
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document.write( "square root of 2y+7 +4=y \n" );
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Algebra.Com's Answer #86187 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! sqrt(2y+7)+4=y \n" ); document.write( "If this is what you mean then: \n" ); document.write( "sqrt(2y+7)=(y-4) \n" ); document.write( "squaring both sides we get: \n" ); document.write( "2y+7=y^2-8y+16 \n" ); document.write( "y^2-8y-2y+16-7=0 \n" ); document.write( "y^2-10y+9=0 \n" ); document.write( "(y-9)(y-1)=0 \n" ); document.write( "y-9=0 \n" ); document.write( "y=9 answer. \n" ); document.write( "y-1=0 \n" ); document.write( "y=1 answer. \n" ); document.write( "proof \n" ); document.write( "sqrt(2*9+7)+4=9 \n" ); document.write( "sqrt(18+7+4)=9 \n" ); document.write( "sqrt25+4=9 \n" ); document.write( "5+4=9 \n" ); document.write( " \n" ); document.write( " |