document.write( "Question 118073: Solve \r
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\n" ); document.write( "\n" ); document.write( "square root of 2y+7 +4=y
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Algebra.Com's Answer #86187 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
sqrt(2y+7)+4=y
\n" ); document.write( "If this is what you mean then:
\n" ); document.write( "sqrt(2y+7)=(y-4)
\n" ); document.write( "squaring both sides we get:
\n" ); document.write( "2y+7=y^2-8y+16
\n" ); document.write( "y^2-8y-2y+16-7=0
\n" ); document.write( "y^2-10y+9=0
\n" ); document.write( "(y-9)(y-1)=0
\n" ); document.write( "y-9=0
\n" ); document.write( "y=9 answer.
\n" ); document.write( "y-1=0
\n" ); document.write( "y=1 answer.
\n" ); document.write( "proof
\n" ); document.write( "sqrt(2*9+7)+4=9
\n" ); document.write( "sqrt(18+7+4)=9
\n" ); document.write( "sqrt25+4=9
\n" ); document.write( "5+4=9
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