document.write( "Question 118075: Solve.\r
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document.write( "A homeowner wishes to insulate her attic with fiberglass insulation to conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between the rafters in the attic. If the roof is 7 m from peak to eave and the attic space is 3 m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth. \n" );
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Algebra.Com's Answer #86184 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A homeowner wishes to insulate her attic with fiberglass insulation to conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between the rafters in the attic. If the roof is 7 m from peak to eave and the attic space is 3 m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth. \n" ); document.write( "---------------- \n" ); document.write( "Draw the picture: you have two right triangles, each with a hypotenuse of 7m \n" ); document.write( "and sharing a height of 3m. \n" ); document.write( "Let the base of one of the triangles be \"x\". \n" ); document.write( "EQUATION: \n" ); document.write( "7^2 = x^2+3^2 \n" ); document.write( "x^2 = 49-9 \n" ); document.write( "x = sqrt40 \n" ); document.write( "=============== \n" ); document.write( "That covers half the length of the rafter. \n" ); document.write( "The full length = 2sqrt40 = 12.65 m \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |