document.write( "Question 118075: Solve.\r
\n" ); document.write( "\n" ); document.write( "A homeowner wishes to insulate her attic with fiberglass insulation to conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between the rafters in the attic. If the roof is 7 m from peak to eave and the attic space is 3 m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth.
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Algebra.Com's Answer #86184 by stanbon(75887)\"\" \"About 
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A homeowner wishes to insulate her attic with fiberglass insulation to conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between the rafters in the attic. If the roof is 7 m from peak to eave and the attic space is 3 m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth.
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\n" ); document.write( "Draw the picture: you have two right triangles, each with a hypotenuse of 7m
\n" ); document.write( "and sharing a height of 3m.
\n" ); document.write( "Let the base of one of the triangles be \"x\".
\n" ); document.write( "EQUATION:
\n" ); document.write( "7^2 = x^2+3^2
\n" ); document.write( "x^2 = 49-9
\n" ); document.write( "x = sqrt40
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\n" ); document.write( "That covers half the length of the rafter.
\n" ); document.write( "The full length = 2sqrt40 = 12.65 m
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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