document.write( "Question 117230: find the equation of the line perpendicular to \"+y+=+-2%2F3x+-+4+\" and passes through (-2,5) \n" ); document.write( "
Algebra.Com's Answer #86180 by misscrt(37)\"\" \"About 
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find the equation of the line perpendicular to \"+y+=+-2%2F3x+-+4+\" and passes through (-2,5)
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\n" ); document.write( "\n" ); document.write( "If the line is perpendicular,its slope will be the negative reciprocal of the original line's slope, m.\r
\n" ); document.write( "\n" ); document.write( "\"y=-2x%2F3-4\"
\n" ); document.write( "is in the form of equation of line----y=mx+b
\n" ); document.write( "So, the original line has a slop of -2/3\r
\n" ); document.write( "\n" ); document.write( "The negative reciprocal of -2/3 is 3/2.\r
\n" ); document.write( "\n" ); document.write( "So, the new line has slope,m=3/2\r
\n" ); document.write( "\n" ); document.write( "Since you are given the point which the new line goes through use the point-slope form to find its equation:\r
\n" ); document.write( "\n" ); document.write( "(x1,y1)=(-2,5)\r
\n" ); document.write( "\n" ); document.write( "(y-y1)=m(x-x1)\r
\n" ); document.write( "\n" ); document.write( "(y-5) = 3/2(x-(-2))\r
\n" ); document.write( "\n" ); document.write( "\"y-5=3%2F2%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-5=3x%2F2+%2B3\"\r
\n" ); document.write( "\n" ); document.write( "Put equation into the standard form,y=mx+b.\r
\n" ); document.write( "\n" ); document.write( "y=3x/2+3 +5\r
\n" ); document.write( "\n" ); document.write( "\"y=3x%2F2+%2B+8\"\r
\n" ); document.write( "\n" ); document.write( "Hope that helps.\r
\n" ); document.write( "\n" ); document.write( "Regards,
\n" ); document.write( "misscrt\r
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