document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=118095>Question 118095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of the segment </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #86165 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=86165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start with the given line segment\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF=\"http://s150.photobucket.com/albums/s91/jim_thompson5910/?action=view&current=drawing.png\" target=\"_blank\"><IMG STYLE=\"max-width:80%;\" src=\"http://i150.photobucket.com/albums/s91/jim_thompson5910/drawing.png\" border=\"0\" alt=\"Photobucket\"></a>\r<BR>\n" );
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document.write( "Draw a line straight down from the right end of the line segment\r<BR>\n" );
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document.write( "From that point, draw a horizontal line to the left end of the line segment. Notice how a right triangle is formed.\r<BR>\n" );
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document.write( "From the picture, we can see that the triangle has legs of 2 and 3 and an unknown hypotenuse (which is the length of the line segment)\r<BR>\n" );
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document.write( "Since we can see that the triangle has legs of 3 and 2 with a hypotenuse of x, we can use Pythagoreans theorem to find the unknown side.\r<BR>\n" );
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document.write( "Pythagoreans theorem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where a and b are the legs of the triangle and c is the hypotenuse\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E2%2B2%5E2=x%5E2 ALIGN=MIDDLE  ALT=\"3%5E2%2B2%5E2=x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Plug in a=3, b=2, and c=x. Now lets solve for x\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9+%2B+4+=++x++%5E+2 ALIGN=MIDDLE  ALT=\"9+%2B+4+=++x++%5E+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square each individual term\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+3+=++x++%5E+2 ALIGN=MIDDLE  ALT=\"1+3+=++x++%5E+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+q+r+t+%28+1+3+%29+=+s+q+r+t+%28++x++%5E+2+%29 ALIGN=MIDDLE  ALT=\"s+q+r+t+%28+1+3+%29+=+s+q+r+t+%28++x++%5E+2+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides\r<BR>\n" );
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document.write( "Which approximates to...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.60555127546399=x ALIGN=MIDDLE  ALT=\"3.60555127546399=x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So our answer to the nearest hundredth is \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=3.61 ALIGN=MIDDLE  ALT=\"x=3.61\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the line segment is about 3.61 units long </SPAN>\n" );
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