document.write( "Question 118039: could you please help me with this problem? i tried it and got 60 pounds but it was wrong.
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document.write( "\"if a dairyman has 300 pounds of milk testing 3% butterfat, how many pounds of skimmed milk (with no butterfat) must he remove to have milk testing 3.6% butterfat?\" \n" );
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Algebra.Com's Answer #86097 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! if a dairyman has 300 pounds of milk testing 3% butterfat, how many pounds of skimmed milk (with no butterfat) must he remove to have milk testing 3.6% butterfat?\" \n" ); document.write( ": \n" ); document.write( "Use this butterfat equation: let x = amt to be removed \n" ); document.write( ": \n" ); document.write( ".03(300) = .036(300 - x) \n" ); document.write( ": \n" ); document.write( "9 = 10.8 - .036x \n" ); document.write( ": \n" ); document.write( "+.036x = 10.8 - 9 \n" ); document.write( ": \n" ); document.write( ".036x = 1.8 \n" ); document.write( ": \n" ); document.write( "x = 1.8/.036 \n" ); document.write( ": \n" ); document.write( "x = 50 lb to be removed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check in original equation \n" ); document.write( ".03(300) = .036(300 - 50) \n" ); document.write( "9 = .036(250) \n" ); document.write( "9 = 9 \n" ); document.write( ": \n" ); document.write( "Hoped this helped & Merry Christmas!! \n" ); document.write( " \n" ); document.write( " |