document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=17294>Question 17294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Agirl has a collection of dimes and nickles worth four dollars. If she has 60 coins,how many of each kind are there?  I don't know how to set up an algebraic equation! please show me the equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8609 by </B><A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><B>LilSkittleMd(119)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 2 equations in this problem. <BR>\n" );
document.write( "Let d= dimes<BR>\n" );
document.write( "Let n= nickels<BR>\n" );
document.write( "d+n=60<BR>\n" );
document.write( "0.1d+0.05n=4<BR>\n" );
document.write( "Use substitution to solve<BR>\n" );
document.write( "n=60-d<BR>\n" );
document.write( "0.1d+0.05(60-d)=4<BR>\n" );
document.write( "0.1d+3-0.05d=4<BR>\n" );
document.write( "0.05d=1<BR>\n" );
document.write( "d=20<BR>\n" );
document.write( "Now substitute d into one of the original equations<BR>\n" );
document.write( "20+n=60<BR>\n" );
document.write( "n=40<BR>\n" );
document.write( "The girl has 20 dimes and 40 nickels </SPAN>\n" );
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