document.write( "Question 117980: Find the equation, in standard form, with all integer coefficients, of the line \r
\n" ); document.write( "\n" ); document.write( "perpendicular to 3x-6y+9 and passing through (-2,-1) \n" ); document.write( "

Algebra.Com's Answer #86020 by checkley71(8403) $\"\"$ $\"About$

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3x-6y+9=0
\n" ); document.write( "-6y=-3x-9
\n" ); document.write( "y=-3x/-6-9/-6
\n" ); document.write( "y=x/2+3/2 this line has a slope=1/2. (red line)
\n" ); document.write( "Therefore a perpendicular line has a slope of -2.
\n" ); document.write( "If it passes through (-2,-1) then we have the equation:
\n" ); document.write( "-1=-2*-2+b
\n" ); document.write( "-1=4+b
\n" ); document.write( "b=-1-4
\n" ); document.write( "b=-5 for the y intercept of this line:
\n" ); document.write( "Thus we have the line equation:
\n" ); document.write( "y=-2x-5 (green line)
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+x%2F2+%2B3%2F2%2C+y+=+-2x+-5%29+\"$ (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = x/2 +3/2 and y = -2x -5). \n" ); document.write( "

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