document.write( "Question 117967: Can you please explain this to me? \r
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document.write( "Divide:
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document.write( "2x^2 + 5x - 12
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document.write( "_______________ divided 2x^2 - 7x + 6
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document.write( "9x^2 - 16 _____________
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document.write( " 3x^2 - x -4\r
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document.write( "thank you
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document.write( "Julie \n" );
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Algebra.Com's Answer #86018 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Divide: \n" ); document.write( "2x^2 + 5x - 12 \n" ); document.write( "_______________ divided 2x^2 - 7x + 6 \n" ); document.write( "9x^2 - 16 _____________ \n" ); document.write( " 3x^2 - x -4\r \n" ); document.write( "\n" ); document.write( "--------------------------------------------- \n" ); document.write( "Factor where you can:\r \n" ); document.write( "\n" ); document.write( "[(2x^2+8x-3x-12)/(3x-4)(3x+4)] / [(2x^2-3x-4x+6)/(3x^2-4x+3x-4)]\r \n" ); document.write( "\n" ); document.write( "=[(2x(x+4)-3(x+4))/(3x-4)(3x+4)] / [(x(2x-3)-2(2x-3))/(x(3x-4)+(3x-4)]\r \n" ); document.write( "\n" ); document.write( "= [(x+4)(2x-3)/(3x-4)(3x+4)] / [(2x-3)(x-2)/(3x-4)(x+1)]\r \n" ); document.write( "\n" ); document.write( "Cancel where you can:\r \n" ); document.write( "\n" ); document.write( "Cancel (2x-3),(3x-4) leaving you with:\r \n" ); document.write( "\n" ); document.write( "= [(x+4)/(3x+4)]/[(x-2)/(x+1)]\r \n" ); document.write( "\n" ); document.write( "Invert the denominator and multiply:\r \n" ); document.write( "\n" ); document.write( "= [(x+4)(x+1)]/[(3x+4)(x-2)]\r \n" ); document.write( "\n" ); document.write( "================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |