document.write( "Question 117666: what are the steps when solving an equation using subatitution \n" ); document.write( "
Algebra.Com's Answer #86011 by checkley71(8403)\"\" \"About 
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x+2y=7 & 3x-2y=-3
\n" ); document.write( "Now we have:
\n" ); document.write( "x+2y=7 or x=-2y+7
\n" ); document.write( "Now substitute (-2y+7) for x in the other equation & solve for y
\n" ); document.write( "3(-2y+7)-2y=-3
\n" ); document.write( "-6y+21-2y=-3
\n" ); document.write( "-8y=-3-21
\n" ); document.write( "-8y=-24
\n" ); document.write( "y=-24/-8
\n" ); document.write( "y=3 answer.
\n" ); document.write( "x+2*3=7
\n" ); document.write( "x+6=7
\n" ); document.write( "x=7-6
\n" ); document.write( "x=1 answer.
\n" ); document.write( "proof
\n" ); document.write( "3*1-2*3=-3
\n" ); document.write( "3-6=-3
\n" ); document.write( "-3=-3\r
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