document.write( "Question 117950: Find two integers, x and x + 1, whose squares differ by 25. \n" ); document.write( "
Algebra.Com's Answer #85980 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If their squares differ by 25, then we have the equation \"%28x%2B1%29%5E2-x%5E2=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%5E2-x%5E2=25\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x%2B1-x%5E2=25\" Foil\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B1=25\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"2x=25-1\"Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x=24\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2824%29%2F%282%29\" Divide both sides by 2 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=12\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"x=12\" \r
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\n" ); document.write( "\n" ); document.write( "Now add 1 to 12 to get the next number. So \"x%2B1=12%2B1=13\"\r
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\n" ); document.write( "\n" ); document.write( "This means our two numbers are 12 and 13\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%5E2-x%5E2=25\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"13%5E2-12%5E2=25\" Plug in the solution\r
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\n" ); document.write( "\n" ); document.write( "\"169-144=25\" Square each term\r
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\n" ); document.write( "\n" ); document.write( "\"25=25\" Subtract. Since the two sides of the equation are equal, this verifies our answer.
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