document.write( "Question 117950: Find two integers, x and x + 1, whose squares differ by 25. \n" ); document.write( "
Algebra.Com's Answer #85979 by bucky(2189)\"\" \"About 
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The two unknown integers are represented by x and by x+1
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\n" ); document.write( "If you square the two integers you get:
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\n" ); document.write( "\"x%5E2\"
\n" ); document.write( "and
\n" ); document.write( "\"%28x%2B1%29%5E2\"
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\n" ); document.write( "Squaring \"%28x%2B1%29\" results in \"%28x%2B1%29%5E2+=+%28x%2B1%29%2A%28x%2B1%29+=+x%5E2+%2B+2x+%2B+1\"
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\n" ); document.write( "If you subtract the two squares, the problem tells you that the result is 25. In equation form
\n" ); document.write( "this subtraction can be expressed as:
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\n" ); document.write( "\"x%5E2+%2B+2x+%2B1+-+x%5E2+=+25\"
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\n" ); document.write( "Notice that in the subtraction the two \"x%5E2\" terms are of opposite sign and therefore
\n" ); document.write( "cancel each other. Therefore, you are left with:
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\n" ); document.write( "\"2x+%2B+1+=+25\"
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\n" ); document.write( "Get rid of the 1 on the left side by subtracting 1 from both sides to get:
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\n" ); document.write( "\"2x+=+24\"
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\n" ); document.write( "Solve for x by dividing both sides of this equation by 2 to reduce the equation to:
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\n" ); document.write( "\"x+=+24%2F2+=+12\"
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\n" ); document.write( "So one of the unknown integers (that is x) equals 12. The other integer is x + 1 and therefore
\n" ); document.write( "it equals 12 + 1 or 13.
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\n" ); document.write( "The two integers you are looking for are 12 and 13.
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\n" ); document.write( "Check. 12 squared is 144 and 13 squared is 169. The difference is 169 - 144 = 25, just as the
\n" ); document.write( "problem requires. So this answer checks and the two integers are 12 and 13.
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\n" ); document.write( "Hope this helps you to understand the problem.
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