document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117942>Question 117942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Whats is      ( (SQRT3) + i ) ^ 9\r<BR>\n" );
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document.write( "or in other words the quantity of the square root of three plus \"i\" to the power of nine in a + bi form </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85974 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What's  ( (SQRT3) + i ) ^ 9<BR>\n" );
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document.write( "Convert to trig form:<BR>\n" );
document.write( "r = sqrt((sqrt3)^2+1^2) = 2<BR>\n" );
document.write( "theta = tan^-1(1/sqrt3)= 30 degrees<BR>\n" );
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document.write( "[2cis(30)]^9 = (2^9)cis(270)<BR>\n" );
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document.write( "Convert back to complex form:\r<BR>\n" );
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document.write( "= 512(cos(270)+isin(270)<BR>\n" );
document.write( "=512(0 + i (-1))<BR>\n" );
document.write( "= -512i<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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