document.write( "Question 117947: sin^2x - sin^4x = (cos^2)(sin^2x)\r
\n" ); document.write( "\n" ); document.write( "sin^2x - (sin^2x)(sin^2x) = (cos^2x)(sin^2x)
\n" ); document.write( "sin^2x - (sin^2x)(1/csc^2x) = (cos^2x)(1/csc^2x)
\n" ); document.write( "sin^2x - (sin^2x/csc^2x) = (cos^2x / csc^2x)\r
\n" ); document.write( "\n" ); document.write( "cos^2x [sin^2x - (sin^2x / csc^2x) = (cos^2x / csc^2x)]\r
\n" ); document.write( "\n" ); document.write( "(sin^2x)(csc^2x) - sin^2x = cos^2x\r
\n" ); document.write( "\n" ); document.write( "(sin^2x)(csc^2x) = cos^2x + sin^2x\r
\n" ); document.write( "\n" ); document.write( "(sin^2x)(csc^2x) = 1\r
\n" ); document.write( "\n" ); document.write( "(1/csc^2x)(csc^2x/1) = 1\r
\n" ); document.write( "\n" ); document.write( "1 = 1\r
\n" ); document.write( "\n" ); document.write( "Can I prove the above identity this way? Or have I taken a leap of faith somewhere along the line?
\n" ); document.write( "Thank you very much.
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Algebra.Com's Answer #85972 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
When you prove identities, you only manipulate one side. So I'm going to change the left side into the right side\r
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\n" ); document.write( "\n" ); document.write( "sin^2x - sin^4x = (cos^2x)(sin^2x).....Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "sin^2x - (sin^2x)(sin^2x) = (cos^2x)(sin^2x).....Rewrite sin^4x as (sin^2x)(sin^2x)\r
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\n" ); document.write( "\n" ); document.write( "sin^2x(1 - sin^2x) = (cos^2x)(sin^2x).....Factor out sin^2x\r
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\n" ); document.write( "\n" ); document.write( "sin^2x(cos^2x) = (cos^2x)(sin^2x).....Replace 1-sin^2x with cos^2x\r
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\n" ); document.write( "\n" ); document.write( "(cos^2x)(sin^2x) = (cos^2x)(sin^2x).....Rearrange the left side\r
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\n" ); document.write( "\n" ); document.write( "So this verifies the identity\r
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