document.write( "Question 117937: Using the foil method, I cant seem to figure this one out. Please help...
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Algebra.Com's Answer #85947 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Do you want to factor this?\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"2x%5E2%2B5x-3\" we can see that the first term is \"2x%5E2\" and the last term is \"-3\" where the coefficients are 2 and -3 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 2 and the last coefficient -3 to get -6. Now what two numbers multiply to -6 and add to the middle coefficient 5? Let's list all of the factors of -6:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -6:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -6\r
\n" ); document.write( "\n" ); document.write( "(1)*(-6)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-3)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(6)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(3)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 5? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 5\r
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First NumberSecond NumberSum
1-61+(-6)=-5
2-32+(-3)=-1
-16-1+6=5
-23-2+3=1
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -1 and 6 add up to 5 and multiply to -6\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"2x%5E2%2B5x-3\", replace \"5x\" with \"-1x%2B6x\" (notice \"-1x%2B6x\" adds up to \"5x\". So it is equivalent to \"5x\")\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2Bhighlight%28-1x%2B6x%29%2B-3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"2x%5E2-1x%2B6x-3\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%5E2-1x%29%2B%286x-3%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x-1%29%2B3%282x-1%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"3\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%282x-1%29\" Since we have a common term of \"2x-1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%5E2-1x%2B6x-3\" factors to \"%28x%2B3%29%282x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"2x%5E2%2B5x-3\" factors to \"%28x%2B3%29%282x-1%29\" (since \"2x%5E2%2B5x-3\" is equivalent to \"2x%5E2-1x%2B6x-3\")\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B5x-3\" factors to \"%28x%2B3%29%282x-1%29\"\r
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