document.write( "Question 117871: Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal
\n" ); document.write( "of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #85938 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
If you create a diagonal in a rectangle, then you have created a right triangle with the diagonal as a hypotenuse. Let's say the short leg of the triangle is x, and then the long leg (the long side of the rectangle) has to be x + 1. And we are given that the hypotenuse is 4 cm.\r
\n" ); document.write( "\n" ); document.write( "Pythagoras tells us that the sides and hypotenuse of a right triangle are related thus:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\", or \"sqrt%28a%5E2%2Bb%5E2%29=c\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Replace a, b, and c with the values we are given:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%5E2%2B%28x%2B1%29%5E2%29=4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Expand the binomial and combine terms under the radical\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%5E2%2Bx%5E2%2Bx%2Bx%2B1%29=4\"
\n" ); document.write( "\"sqrt%282x%5E2%2B2x%2B1%29=4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Square both sides:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B2x%2B4=16\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add -16 to both sides:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B2x-15=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use the quadratic formula\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A2%2A%28-15%29%29%29%2F%282%2A2%29+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+124%29%29%2F4+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+2sqrt%28+31%29%29%2F4+\", so\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\"x%5B1%5D+=+%28-1+%2B+sqrt%28+31%29%29%2F2+\", or
\n" ); document.write( "\"x%5B2%5D+=+%28-1+-+sqrt%2831%29%29%2F2\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5B2%5D+%3C+0\" so we can exclude this answer because we are looking for a positive number length.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since \"sqrt%2831%29%3E5\", \"x%5B1%5D%3E0\", so \"x%5B1%5D+=+%28-1+%2B+sqrt%28+31%29%29%2F2+\" is the answer we are seeking and is the width of the rectangle. The length of the rectangle is \"x%2B1\", so the length must be \"%28%28-1+%2B+sqrt%28+31%29%29%2F2%29%2B1+=%281+%2B+sqrt%28+31%29%29%2F2%29\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps,
\n" ); document.write( "Happy Holidays,
\n" ); document.write( "John\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );