document.write( "Question 117932: If 3x^2-2x+7=0, Then (x-1/3)^2= \n" ); document.write( "

Algebra.Com's Answer #85935 by checkley71(8403) $\"\"$ $\"About$

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3x^2-2x+7=0
\n" ); document.write( "using the quadratic equation we get:
\n" ); document.write( "x=(2+-sqrt[-2^2+4*3*7])/2*3
\n" ); document.write( "x=(2+-sqrt[4-84])/6
\n" ); document.write( "x=(2+-sqrt-80)/6
\n" ); document.write( "x=(2+-8.944i)/6
\n" ); document.write( "x=2/6-8.944i/6
\n" ); document.write( "x=1/3+1.49i answer.
\n" ); document.write( "x=1/3-1.49i answer.
\n" ); document.write( "then:
\n" ); document.write( "(x-1/3)^2=(1/3+1.49i-1/3)^2=(1.49i)^2=-2.22 answer.
\n" ); document.write( "or (x-1/3)^2=(1/3-1.49i-1/3)^2=(-1.49i)^2=-2.22 answer.
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