document.write( "Question 17807: Please help!!!
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document.write( "Preston antifreeze is 20% antifreeze and Icefree is 12% antifreeze. How much of each should be used to get a 22 quart mixture of 15% antifreeze?\r
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document.write( "Thanks in advance
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Algebra.Com's Answer #8592 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Preston antifreeze is 20% antifreeze and Icefree is 12% antifreeze. How much of each should be used to get a 22 quart mixture of 15% antifreeze?\r \n" ); document.write( "\n" ); document.write( "total qty.of mixture =22 quarts \n" ); document.write( "let preston in the mix =x quarts \n" ); document.write( "so icefree in the mix =22-x quarts \n" ); document.write( " Preston antifreeze is 20% antifreeze ..so x quarts would have x*20/100=x/5 quarts..anti freeze \n" ); document.write( "Icefree is 12% antifreeze..so 22-x quarts would have (22-x)*12/100=3(22-x)/25 \n" ); document.write( "=(66-3x)/25 quarts..antifreeze.. \n" ); document.write( "so total antifreeze in the mix =x/5+(66-3x)/25... \n" ); document.write( "but the final mix had 15% antifreeze..in 22 quarts total antifreeze is =22*15/100=33/10...hence we have \n" ); document.write( "x/5+(66-3x)/25=33/10 \n" ); document.write( "((5x+66-3x)/25)=33/10 \n" ); document.write( "(2x+66)/25=33/10 \n" ); document.write( "2x+66=33*25/10=165/2 \n" ); document.write( "2x=165/2-66=(165-2*66)/2=(165-132)/2=33/2... \n" ); document.write( "x=33/(2*2)=33/4 = 8.25 quarts of preston and \n" ); document.write( "22-x=22-8.25=13.75 quarts of icefree \n" ); document.write( " \n" ); document.write( " |