document.write( "Question 117899: A ball is thrown upward from the roof of a building 100 m tall with an initial velocity of 20 m/s. \r
\n" ); document.write( "\n" ); document.write( "When will the ball reach a height of 80 m?
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Algebra.Com's Answer #85889 by ankor@dixie-net.com(22740)\"\" \"About 
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A ball is thrown upward from the roof of a building 100 m tall with an initial velocity of 20 m/s.
\n" ); document.write( "When will the ball reach a height of 80 m?
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\n" ); document.write( "I assume they mean 80 m above the ground so it will at 80 m it, be 20 m below the top of the building.
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\n" ); document.write( "The equation:
\n" ); document.write( "h = -4.9t^2 + 20t + 100
\n" ); document.write( "Where
\n" ); document.write( "h is the height of the ball after t seconds
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\n" ); document.write( "-4.9t^2 is the force of gravity, negative because it pulls downward
\n" ); document.write( "+20x is the velocity of the ball upward
\n" ); document.write( "100 is the initial height when the ball is thrown
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\n" ); document.write( "To solve:
\n" ); document.write( "-4.9t^2 + 20t + 100 = 80 m
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\n" ); document.write( "-4.9t^2 + 20t + 100 - 80 = 0
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\n" ); document.write( "-4.9t^2 + 20t + 20 = 0; a quadratic equation that we can solve
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\n" ); document.write( "Use the quadratic formula to solve this a=-4.9; b = 20; c = 20
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\n" ); document.write( "I got the positive solution of 4.9 seconds (rounded off)
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\n" ); document.write( "Check solution in -4.9t^2 + 20t + 100 = h
\n" ); document.write( "-4.9(4.9^2) + 20(4.9) + 100 =
\n" ); document.write( "-4.9(24) + 98 + 100 =
\n" ); document.write( "-117.6 + 98 + 100 = 80.4 ~ 80
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