document.write( "Question 117899: A ball is thrown upward from the roof of a building 100 m tall with an initial velocity of 20 m/s. \r
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document.write( "When will the ball reach a height of 80 m?
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Algebra.Com's Answer #85889 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A ball is thrown upward from the roof of a building 100 m tall with an initial velocity of 20 m/s. \n" ); document.write( "When will the ball reach a height of 80 m? \n" ); document.write( ": \n" ); document.write( "I assume they mean 80 m above the ground so it will at 80 m it, be 20 m below the top of the building. \n" ); document.write( ": \n" ); document.write( "The equation: \n" ); document.write( "h = -4.9t^2 + 20t + 100 \n" ); document.write( "Where \n" ); document.write( "h is the height of the ball after t seconds \n" ); document.write( ": \n" ); document.write( "-4.9t^2 is the force of gravity, negative because it pulls downward \n" ); document.write( "+20x is the velocity of the ball upward \n" ); document.write( "100 is the initial height when the ball is thrown \n" ); document.write( ": \n" ); document.write( "To solve: \n" ); document.write( "-4.9t^2 + 20t + 100 = 80 m \n" ); document.write( ": \n" ); document.write( "-4.9t^2 + 20t + 100 - 80 = 0 \n" ); document.write( ": \n" ); document.write( "-4.9t^2 + 20t + 20 = 0; a quadratic equation that we can solve \n" ); document.write( ": \n" ); document.write( "Use the quadratic formula to solve this a=-4.9; b = 20; c = 20 \n" ); document.write( ": \n" ); document.write( "I got the positive solution of 4.9 seconds (rounded off) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in -4.9t^2 + 20t + 100 = h \n" ); document.write( "-4.9(4.9^2) + 20(4.9) + 100 = \n" ); document.write( "-4.9(24) + 98 + 100 = \n" ); document.write( "-117.6 + 98 + 100 = 80.4 ~ 80 \n" ); document.write( " \n" ); document.write( " |