document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117895>Question 117895</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I hope I am posting this in the correct place. I am really stuck on this and do not know what to do. Please help me understand how to do this, Thank you so much.<BR>\n" );
document.write( "2{[3(m-5)+18]-[3(5m-3)+4]} </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85881 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20056)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><font face = \"book antiqua\" size = 4><b>\r\n" );
document.write( "2{[3(m-5)+18]-[3(5m-3)+4]}\r\n" );
document.write( "\r\n" );
document.write( "First look for the first innermost pair of grouping symbols.\r\n" );
document.write( "That is, grouping sysmbols which have no grouping symbols \r\n" );
document.write( "between them.  So we see (m-5).\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"Is there anything which we can do with what is\r\n" );
document.write( "inside \" m-5 \". \r\n" );
document.write( "\r\n" );
document.write( "The answer is no.  \r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"How do we remove those grouping symbols around\r\n" );
document.write( "\" m-5 \"?\"\r\n" );
document.write( "\r\n" );
document.write( "The answer is by distributing the 3 just outside the (m-5),\r\n" );
document.write( "getting 3m-15, so in place of 3(m-5) we write 3m-15, and\r\n" );
document.write( "copy everything else over, getting\r\n" );
document.write( "\r\n" );
document.write( "2{[3m-15+18]-[3(5m-3)+4]}\r\n" );
document.write( "\r\n" );
document.write( "-----------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "Now we start over. Look for the first innermost pair of \r\n" );
document.write( "grouping symbols. That is, grouping sysmbols which have \r\n" );
document.write( "no grouping symbols between them.  So we see [3m-15+18].\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"Is there anything which we can do with what is\r\n" );
document.write( "inside \"3m-15+18\". \r\n" );
document.write( "\r\n" );
document.write( "The answer is yes, we can combine the -15 and the +18 getting\r\n" );
document.write( "\"3m+3\".  So we replace \"3m-15+18\" by \"3m+3\", and copy \r\n" );
document.write( "everything else over:\r\n" );
document.write( "\r\n" );
document.write( "2{[3m+3]-[3(5m-3)+4]}   \r\n" );
document.write( "\r\n" );
document.write( "---------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "Now we start over. Look for the first innermost pair of \r\n" );
document.write( "grouping symbols. That is, grouping sysmbols which have \r\n" );
document.write( "no grouping symbols between them.  So we see [3m+3].\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"How do we remove those grouping symbols around\r\n" );
document.write( "3m+3?\"\r\n" );
document.write( "\r\n" );
document.write( "The answer is by putting the invisible 1 just left of [3m+3],\r\n" );
document.write( "like this:\r\n" );
document.write( "\r\n" );
document.write( "2{1[3m+3]-[3(5m-3)+4]}\r\n" );
document.write( "\r\n" );
document.write( "and distributing the 1 just outside the [3m+3],\r\n" );
document.write( "getting 3m+3, so in place of [3m+3] we write 3m+3, and\r\n" );
document.write( "copy everything else over, getting\r\n" );
document.write( "\r\n" );
document.write( "2{3m+3-[3(5m-3)+4]}\r\n" );
document.write( "\r\n" );
document.write( "---------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "Now we start over again. Look for the first innermost pair of \r\n" );
document.write( "grouping symbols. That is, grouping symbols which have \r\n" );
document.write( "no grouping symbols between them.  So we see (5m-3).\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"Is there anything which we can do with what is\r\n" );
document.write( "inside, that is, \"5m-3\". \r\n" );
document.write( "\r\n" );
document.write( "The answer is no.  \r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"How do we remove those grouping symbols around\r\n" );
document.write( "\" 5m-3 \"?\r\n" );
document.write( "\r\n" );
document.write( "The answer is by distributing the 3 just outside the (5m-3),\r\n" );
document.write( "getting 15m-9, so in place of 3(5m-3) we write 15m-9, and\r\n" );
document.write( "copy everything else over, getting\r\n" );
document.write( "\r\n" );
document.write( "2{3m+3-[15m-9+4]}\r\n" );
document.write( "\r\n" );
document.write( "--------------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "Once more, we start over. Look for the first innermost pair \r\n" );
document.write( "of grouping symbols. That is, grouping sysmbols which have \r\n" );
document.write( "no grouping symbols between them.  So we see [15m-9+4].\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"Is there anything which we can do with what is\r\n" );
document.write( "inside, namely, \"15m-9+4\". \r\n" );
document.write( "\r\n" );
document.write( "The answer is yes. The answer is yes, we can combine the -9 \r\n" );
document.write( "and the +4 getting \"15m-5\".  So we replace \"15m-9+4\" by \"15m-5\",\r\n" );
document.write( "and copy everything else over:\r\n" );
document.write( "\r\n" );
document.write( "2{3m+3-[15m-5]}   \r\n" );
document.write( "\r\n" );
document.write( "-----------------------------\r\n" );
document.write( "\r\n" );
document.write( "Once more, we start over. Look for the first innermost pair \r\n" );
document.write( "of grouping symbols. That is, grouping sysmbols which have \r\n" );
document.write( "no grouping symbols between them.  So we see [15m-5].\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"Is there anything which we can do with what is\r\n" );
document.write( "inside, namely, \"15m-5\". \r\n" );
document.write( "\r\n" );
document.write( "The answer is no.\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"How do we remove those grouping symbols around\r\n" );
document.write( "15m-5?\"\r\n" );
document.write( "\r\n" );
document.write( "The answer is by putting the invisible 1 just left of [15m-5],\r\n" );
document.write( "like this:\r\n" );
document.write( "\r\n" );
document.write( "2{3m+3-1[15m-5]}\r\n" );
document.write( "\r\n" );
document.write( "and distributing the -1 just outside the [15m-5],\r\n" );
document.write( "getting -15m+5, so in place of -1[15m-5] we write -15m+5, and\r\n" );
document.write( "copy everything else over, getting\r\n" );
document.write( "\r\n" );
document.write( "2{3m+3-15m+5}\r\n" );
document.write( "\r\n" );
document.write( "--------\r\n" );
document.write( "\r\n" );
document.write( "Now we start over again. Look for the first innermost pair of \r\n" );
document.write( "grouping symbols. That is, grouping symbols which have \r\n" );
document.write( "no grouping symbols between them.  So we see {3m+3-15m+5}.\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"Is there anything which we can do with what is\r\n" );
document.write( "inside, namely \" 3m+3-15m+5 \". \r\n" );
document.write( "\r\n" );
document.write( "The answer is yes, we can combine the 3m and the -15m, and also\r\n" );
document.write( "the +3 and the +5, getting \"-12m+8\".  So we replace \"3m+3-15m+5\"\r\n" );
document.write( "by \"-12m+8\", and copy everything else over:\r\n" );
document.write( "\r\n" );
document.write( "2{-12m+8}   \r\n" );
document.write( "\r\n" );
document.write( "---------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "Starting over again, we look for the first innermost pair of \r\n" );
document.write( "grouping symbols. That is, grouping sysmbols which have no \r\n" );
document.write( "grouping symbols between them.  So we see {-12m+8}.\r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"Is there anything which we can do with what is\r\n" );
document.write( "inside, namely, \" -12m+8 \". \r\n" );
document.write( "\r\n" );
document.write( "The answer is no.  \r\n" );
document.write( "\r\n" );
document.write( "Then we ask: \"How do we remove those grouping symbols around\r\n" );
document.write( "\" -12m+8 \"?\"\r\n" );
document.write( "\r\n" );
document.write( "The answer is by distributing the 2 just outside the {-12m+8},\r\n" );
document.write( "getting -24m+16, so in place of 2{-12m+8} we write -24m+16.\r\n" );
document.write( "\r\n" );
document.write( "There are no grouping symbols and nothing else can be done with\r\n" );
document.write( "-24m+16, so we are done.\r\n" );
document.write( "\r\n" );
document.write( "The answer is -24m+16.\r\n" );
document.write( "\r\n" );
document.write( "Edwin</PRE> </SPAN>\n" );
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