document.write( "Question 117841This question is from textbook
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document.write( ": i want to know how to set up a problem like this for setting up linear equations\r
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document.write( "three pens and two notebooks cost $8.25. Two pens and three notebooks cost $8.00. How much would two pens and two notebooks cost \n" );
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Algebra.Com's Answer #85833 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! three pens and two notebooks cost $8.25. Two pens and three notebooks cost $8.00. How much would two pens and two notebooks cost \n" ); document.write( "--------------- \n" ); document.write( "Let the cost of one pen be \"p\"; Let the cost of one notebook be \"n\". \n" ); document.write( "--------------- \n" ); document.write( "EQUATIONS: \n" ); document.write( "3p + 2n = 8.25 \n" ); document.write( "2p + 3n = 8.00 \n" ); document.write( "------------------- \n" ); document.write( "Multiply thru 1st by 2; Multiply thru 2nd by 3. \n" ); document.write( "---------------- \n" ); document.write( "6p + 4n = 16.50 \n" ); document.write( "6p + 9n = 24.00 \n" ); document.write( "--------------- \n" ); document.write( "Substract 1st from 2nd to solve for \"n\": \n" ); document.write( "5n = 7.50 \n" ); document.write( "n = $1.50 (cost of one notebook) \n" ); document.write( "---------- \n" ); document.write( "Substitute to solve for \"p\": \n" ); document.write( "6p + 4(1.50) = 16.50 \n" ); document.write( "6p + 6.00 = 16.50 \n" ); document.write( "6p = 10.50 \n" ); document.write( "p = $1.75 (cost of one pen) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |